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  1. #1
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    Post Question Of The Day (19-March-17)

    Question Of The Day (19-March-17)



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  2. #2
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    Post Question Of The Day (19-March-17)

    Last edited by TestFunda; 20-Mar-17 at 12:48 PM.

  3. #3
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    Default Very Tough

    Am feeling very tough when seeing this solved problem.

  4. #4
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    Post Question Of The Day (19-March-17)

    @ TestFunda,

    for 'a' to be an integer, 9 should be divisible by x.

    thus, x cannot just be any number greater than 3.
    (for eg, if x=10, a=10.9 (9/10+10=10.9)- NOT POSSIBLE

    Kindly correct your range of 'p'.
    it should be from (49,96)

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