   
Puzzle #490  Blast from the Past
Puzzle #490  Blast from the Past
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Puzzle #490  Blast from the Past
Let Newton be 1(True) and Oldton be 0(False).
Case 1: If Alex is true,
Alex is 1 > Barney is 0 > Charlie is 1 > Darren is 0
Case 2: If Alex is false,
Alex is 0 > Barney is 1 > Charlie is 0 > Darren is 1
When it was asked from Darren that what would Alex say about Charlie. He said, Alex will say Charlie is 0.
This case is applicable for Case 2 only. Thus Darren is 1(True). Hence Darren is Newton 

Puzzle #490  Blast from the Past
Originally Posted by ANUBHAV24529 Let Newton be 1(True) and Oldton be 0(False).
Case 1: If Alex is true,
Alex is 1 > Barney is 0 > Charlie is 1 > Darren is 0
Case 2: If Alex is false,
Alex is 0 > Barney is 1 > Charlie is 0 > Darren is 1
When it was asked from Darren that what would Alex say about Charlie. He said, Alex will say Charlie is 0.
This case is applicable for Case 2 only. Thus Darren is 1(True). Hence Darren is Newton Your answer is incorrect. I will not say the correct solution because of two reasons:
1. It is better if you find out the mistake yourself. It will help you improve your skills.
2. We are not supposed to discuss solutions until results are declared.


Puzzle #490  Blast from the Past
Suppose, A >N (truth teller)
B >O(liar)
C>N(truth teller)
D>O(liar)
Now when asked from D if A would call C a newton or an Oldton, he lied which means, A would say that C is a Newton and because A is a truth teller he is saying right which is also the case we assumed.
So, D is an Oldton

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