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Thread: Let's Bell The CAT Together

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    Invisible aaamresh's Avatar
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    Post Let's Bell The CAT Together

    Hi Guys,
    Since only 2 months are left so we all need more and more practice. Here we get only a single question for the whole day. So I request you all to post some good questions covering every section under the above mentioned heading everyday. So come on guys let's bell the CAT together........
    enjoy studying
    (Amresh Singh)

    Here is a question for you,

    In an election for the president, 261 valid votes are cast, for the 5 contestants. Find the least number of votes a candidate requires to receive to win the election. No candidate gets less than 50 votes.

    1) 53
    2) 54
    3) 55
    4) 56
    5) 57
    edited by aaamresh on 9/15/2008
    edited by aaamresh on 10/3/2008
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    Post Let''s Bell The CAT Together

    Quote Originally Posted by aaamresh
    Hi Guys,
    Since only 2 months are left so we all need more and more practice. Here we get only a single question for the whole day. So I request you all to post some good questions covering every section under the above mentioned heading everyday (don't forget to change the date). So come on guys let's bell the CAT together........
    enjoy studying
    (Amresh Singh)

    Here is a question for you,

    In an election for the president, 261 valid votes are cast, for the 5 contestants. Find the least number of votes a candidate requires to receive to win the election.

    1) 53
    2) 54
    3) 55
    4) 56
    5) 57

    Answer 53.
    For minimum number all should be very close to each other. 261/5 = 52.2
    So, winner gets 53 votes and the other 4 get 52 votes each.

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    Post Let''s Bell The CAT Together

    option (a) 53

    as 261 votes are there and 5 candidates...so divide by 5 ..260/5 = 52...so now all 5 candidates have 52 votes each and 1 vote is left so that will goto one of the candidate and he/she will win..so least no. of votes required = 53
    aditya4786 likes this.
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    Post Let''s Bell The CAT Together

    hello amit & sumit,

    i have updated the question by adding a line " no candidate gets less than 50 votes"

    if your answer is still the same then,
    Is getting 53 votes ensures a win?
    there may be a tie as contestant gets 53,53,52,52,51 votes.
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    Post Let''s Bell The CAT Together

    Quote Originally Posted by aaamresh
    hello amit & sumit,

    i have updated the question by adding a line " no candidate gets less than 50 votes"

    if your answer is still the same then,
    Is getting 53 votes ensures a win?
    there may be a tie as contestant gets 53,53,52,52,51 votes.
    Hi aamresh
    if u change the question such that no candidate gets less than 50 votes then the ans canl be option (4) 56

    as in that case ..as each candidate gets atleast 50 votes...so total 250 votes have been cast..with each having 50 votes
    now 11 votes are left..we can have two persons with 55 55 votes and still one vote left..so give that to one person and hsi count becomes 56...so votes required is 56

    One Query

    here you have asked least no. of votes required to win the election , that will be 53 only as that is the least no. of votes with other conditions favourable for a candidate to win the exam

    if you are asking no. of votes necessarily needed to win...then the answer will be 56 as stated above

    so i will say regardless of the extra condition least no. of votes = 53 only
    what say
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    Post Let''s Bell The CAT Together

    Quote Originally Posted by aaamresh

    Here is a question for you,
    In an election for the president, 261 valid votes are cast, for the 5 contestants. Find the least number of votes a candidate requires to receive to win the election. No candidate gets less than 50 votes.
    The answer is 53....
    Sure... I did it by trial and error method....

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    Post Let''s Bell The CAT Together

    As sumit said if the coundtion is 'least no. of votes required to win the election ' answer is 53 for sure.

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    Post Let''s Bell The CAT Together

    yes question is asking "least no. of votes required to win the election"

    it is not asking "least no. of votes so that a candidate may win the election"

    so i will go with the option (4).

    There was a question in CAT 2007, which i think will clear your doubt.
    here it is.......

    In a football match, at the half time, M&M club was trailing by 3 goals. Did it win the match?
    A) In the second half M&M club scored 4 goals.
    B) The opponent scored 4 goals in the match.

    Mark (1) if the question can be answered by using statement A alone but not by using statement B alone
    Mark (2) if the question can be answered by using statement B alone but not by using statement A alone
    Mark (3) if the question can be answered by using either of the statements alone
    Mark (4) if the question can be answered by using both the statements together
    Mark (5) if the question can't be answered on the basis of the two statements


    It is clear that the question can't be answered by using either statements alone. Let's consider both the statements together. Under this condition 2 cases are possible.
    Let opponent team is A
    CASE 1 :-

    A M&M
    first half 3 0
    second half 1 4
    total goals 4 4
    RESULT= A TIE

    CASE 2:-
    A M&M
    first half 4 1
    second half 0 4
    total goals 4 5
    RESULT= M&M WON

    So what should be the answer 4 or 5
    Obviously it should be 5.

    This question is quite similar to what i asked.
    So Sumit what should be the answer 53 or 56?
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    Post Let''s Bell The CAT Together

    Here is another question in advance........

    Find the square root of ( 32 - ?1020 ).

    1) ?15 + ?17
    2) ?13 - ?11
    3) ?17 - ?15
    4) ?13 + ?11
    5) ?18 - ?14

    you people are not posting the questions. it's not fair.
    ok guys goodnight.........
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    Post Let''s Bell The CAT Together

    answer is 3.

    as 1020/4 = 255 = 15*17 and 15+17 = 32

    so it is (?15 )^2 + (?17)^2 - 2[ ?15 *?17]
    which is equal to square of ans 3...
    so the ans is 3

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    Post Let''s Bell The CAT Together

    Answer is 3.

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    Post Let''s Bell The CAT Together

    Here is one more....

    In how many maximum different ways can 3 identical balls be placed in the 12 squares (each ball to be placed in the exact center of the squares and only one ball is to be placed in one square) shown in the figure given below such that they do not lie along the same straight line?

    _ _ _ _
    l_l_l_l_l
    l_l_l_l_l
    l_l_l_l_l


    1) 144
    2) 200
    3) 204
    4) 208
    5) 216
    edited by aaamresh on 9/15/2008
    edited by aaamresh on 9/15/2008
    edited by aaamresh on 9/16/2008
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    Post Let''s Bell The CAT Together

    the question for the DS question discussed above will be 5 only.......

    as far as no. of votes question go ...i cant seem to leave 53....

    can you post the original solution of the problem ...probaly that will clear things up
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    Post Let''s Bell The CAT Together

    i am assuming that with straight lines you are just considering horizontal and vertical and not diagonal

    answer is option (1) 144

    first ball can be placed in 12 ways in any of the squares (refer to the image that i have attached alongside)

    now second ball cant be placed in the same row vertically or horizontally as the first ball...so there are 6 ways to place it..

    and lastly the third ball can be placed in 2 ways

    so total no. of ways = 12*6*2 = 144
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    Post Let''s Bell The CAT Together

    A new question

    there are 4 letters and 4 envelopes. The no. of ways in which all the letters can be put in the wrong envelope is

    a) 8
    b) 9
    c) 16
    d) none of these
    edited by sumit2goody on 9/16/2008
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    Post Let''s Bell The CAT Together

    yes sumit you have to consider the diagonal arrangement also. that is the main point of the question. if u gonna miss it, your answer will be wrong.

    there are 4 letters and 4 envelops. first letter can be placed in 4 ways, second can be placed in 3 ways since one envelope is occupied now, third can be placed in 2 ways and last one can be placed in 1 way.
    therefore total no. of placing the letters are = 4*3*2*1= 24
    no. of ways of placing the letters in their respective envelopes is 1.
    hence required answer is = 24 - 1 = 23.

    hence ans is option 4.
    edited by aaamresh on 9/16/2008
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    Post Let''s Bell The CAT Together

    ok i will try the diagonal condition also and will try it out

    the answer you have posted for letters problem is wrong because you are only subtracting the case in which all the letters are in their correct positions , the question statement says that all letters are at wrong places...so consider that also and try again
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    Post Let''s Bell The CAT Together

    sorry i got it now
    total no.of ways= 24
    all 4 can be placed correctly in 1 way.
    3 of them can be placed correctly in 4 ways.
    2 of them can be placed correctly in 6 ways.
    1 of them can be placed correctly in 4 ways.
    this make 15 ways.
    hence required answer is= 24 - 15 = 9
    hence option (b).

    is it correct????????
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    Post Let''s Bell The CAT Together

    one more.........

    There are 6 different letters and 6 correspondingly addressed envelopes. If the letters are randomly put in the envelopes, what is the probability that exactly 5 letters go into the correctly addressed envelopes?

    1) Zero
    2) 1/6
    3) 1/2
    4) 5/6
    5) none of these
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    Post Let''s Bell The CAT Together

    Aamresh wrote:

    sorry i got it now
    total no.of ways= 24
    all 4 can be placed correctly in 1 way.
    3 of them can be placed correctly in 4 ways.
    2 of them can be placed correctly in 6 ways.
    1 of them can be placed correctly in 4 ways.
    this make 15 ways.
    hence required answer is= 24 - 15 = 9
    hence option (b).

    is it correct????????

    I have a doubt here - how can we consider the case that when 3 of them is placed correctly because if 3 are placed correctly then the 4th one will automatically be correct...

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