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TestFunda Answers  Higher Maths
option 1..265 classic case of dearrangements. nos. of ways = 6!*(1 1/1! + 1/2!  1/3! + 1/4!  1/5! + 1/6!) = 265 

TestFunda Answers  Higher Maths
if the sets are identical then option B otherwise if are considered as different like Set 1 Set 2 etc. then option D 

TestFunda Answers  Higher Maths
Three consecutive positive integers are raised to the first, second and third powers respectively and then added. The sum so obtained is a perfect square whose square root equals the total of the three original integers. Which of the best describes the minimum value say m of these three integers?  Options  1)  1<=m<=3  2)  4<=m<=6  3)  7<=m<=9  4)  10<=m<=12  5)  13<=m<=15 



TestFunda Answers  Higher Maths
A person wrote first N consecutive numbers (natural) on a board and found their sum, Another person came and deleted the smallest number and found the sum of remaaining numbers. The process continued until N remained on the board. The average of all the sums is found to out to be 105. Find N?  Options  


TestFunda Answers  Higher Maths
X and Y belong to the set of positive integers. The probability that a randomly chosen value of Y satisfies the equation 3X13Y= 2 is:  Options  1)  1/8  2)  2/3  3)  3/13  4)  Cannot be determined 



TestFunda Answers  Higher Maths
Karan and Arjun run a 100 metre race, where Karan beats Arjun by 10 metres. To do a favour to Arjun, Karan starts 10 metres behind the starting line in a second 100 metre race. They both run at their earlier speeds. Which of the following is true in connection with the second race?  Options  1)  Karan and Arun reach the finishing line simultaneously.  2)  Arjun beats Karan by 1 metre.  3)  Arjun beats Karan by 11 metre.  4)  Karan beats Arjun by 1 metre. 



TestFunda Answers  Higher Maths
After travelling 50km, a train is meeting with an accident and travels at 3/4th of the usual speed and reaches 45 min late. Had the accident happened 10km further on it would have reached 35 min late. Find the usual speed?  Options  1)  15 km/hr  2)  20 km/hr  3)  25 km/hr  4)  30 km/hr 



TestFunda Answers  Higher Maths
Let three integers be x1, x & x+1. Now acc. to question x1 + x^2 + (x+1)^3 = (3x)^2 Solving equation we will have x= 0,1,4. x cannot be 0, 1 as numbers are positive integers, so x= 4.
So integers are 3,4,5. And our answer is 3. 

TestFunda Answers  Higher Maths
Three wheels can complete 60, 36, 24 revolutions per minute respectively. There is a spot on each wheel that touches the ground at time zero. After how much time, all these spots will simultaneously touch the ground again:  Options  1)  5/2 sec  2)  5/3 sec  3)  6 sec  4)  7.5 sec 



TestFunda Answers  Higher Maths
option 2..20 Kph let total distance be 'd', original speed of train be 's' and time taken to reach d be 't' d/s = t now, d/s + 4(d50)/3s = d/s + 3/4 ...............eq.1 d/s + 4(d60)/3s = d/s + 7/12 ...............eq.2 solving eq.1 and eq.2...we get s = 20 Kph 

TestFunda Answers  Higher Maths
option 4...karan beats arjun by 1 meter from 1st race: S _{karan} / S _{arjun} = 10/9 ....let their speeds be 10m/s and 9 m/s respectively. in 2nd race Karan runs 110 mtrs to complete the race, i.e., he takes 11 seconds to complete the racing distance of 100 mtrs. In this 11 secs Arjun runs 9*11 = 99mtrs Therefore, Karan beats Arjun by 1 mtr in the 2nd race 

TestFunda Answers  Higher Maths
option 2..2/3
Upon removing the modulus sign, we get (3x13y) = +2 and (3x13y) = 2, Solving we see that y exists for positive integers (1,2,4,5,7,8,10,11,â€¦..) values like 3,6,9,12,â€¦.. cannot satisfy the equation for positive integer values of xâ€¦.. hence ,probability is 2/3


TestFunda Answers  Higher Maths
option 1...17 The sum of the series can be writen as 1*1 + 2*2 + 3*3 + ........ + n*n = n*(n+1)*(2n+1)/6 now, (n+1)*(2n+1)/6 = 105 {given, average of sum of n series as 105} solving: n = 17 

TestFunda Answers  Higher Maths
If the same 100 apples had to be divided among 8 people instead of 5 in a similar manner, then how many apples will the eighth person get, if the no.of apples the first person gets is unchanged?  Options  1)  70/3  2)  65/6  3)  115/3  4)  Indeterminate 



TestFunda Answers  Higher Maths
is a,a,a,a,a,a,a,a,a................. an A.P? if yes then how and what will be the sum of n terms in the series and if no then why. 


TestFunda Answers  Higher Maths
how it can be an A.P all terms are equal to its first term and all of them had a common difference of 0..................................................i dont think it is in progressions
try to use A.M >= G.M ARITHMETIC MEAN GREATER THAN OR EQUAL TO GEOMETRIC MEAN CAN BE ONE APPROACH IF ITS SOLUTION EXIST 

TestFunda Answers  Higher Maths
A shipping clerk has five boxes of different but unknown weights each weighing less than 100 kgs. The clerk weighs the boxes in pairs. The weights obtained are 110,112, 113, 114, 115, 116, 117, 118, 120 and 121 kgs. What is the weight, in kgs, of the heaviest box?  Options  1)  60  2)  62  3)  64  4)  cannot be determined 
 Additional Notes: Explain ur method 


TestFunda Answers  Higher Maths
it's in an AP with the common diff. 0. as the sum of AP is given by n/2(2a+(n1)d= n/2(2a)=an 

TestFunda Answers  Higher Maths
what is the total no. of ways of selecting twenty balls from an infinite no. of blue,green and yellow balls?  Options  1)  3^20  2)  20^3  3)  231  4)  1771 
 Additional Notes: please help why cant the ans to this ques be 3^20?? 


TestFunda Answers  Higher Maths
No. of ways for finding 1st ball out of the 3 types = 3 No. of ways for finding 2nd ball out of the 3 types = 3 Similarly for 3rd ball=3, 4th ball=3,.... Thus, for 20 balls = 3^20 
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