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Thread: TestFunda Answers - Higher Maths

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    Post TestFunda Answers - Higher Maths

    how many 4 digit numbers divisible by 5 can be formed with the digits 0,1,2,3,4,5,6and6?
    Options
    1) 
    220
    2) 
    249
    3) 
    432
    4) 
    288
    5) 
    216

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    Post TestFunda Answers - Higher Maths


    There are five thieves, each loot a shop one after the other such that the first one takes 1/2 of the total no. of the Chocolates plus 1/2 of a Chocolate. Similarly 2nd, 3rd,4th  and 5th also did the same. After the fifth one no. of  Chocolates remained are 3. Initially how many Chocolates were there?


    Options
    1) 
    124
    2) 
    125
    3) 
    126
    4) 
    127

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    Post TestFunda Answers - Higher Maths

    Rahul is sailing at a uniform speed when a leak develops in his boat. He uses a bucket to empty water from the boat and reaches the shore in 30 minutes just in time to avoid sinking. The leak fills the boat twice as fast as the Rahul is able to empty it. Had the leak developed 10 minutes earlier how much faster would the Rahul have had to work to reach the shore safely ?
    Options
    1) 
    20
    2) 
    25
    3) 
    30
    4) 

    35


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    Post TestFunda Answers - Higher Maths


    Q. Rahul lends Rs 3600 on simple interest to Shyam for a period of 5 years. He lends a part of the amount at 4% interest and the rest at 6% and receives Rs. 960 as the amount of interest. How much money did he lend on 4% interest rate?


    Options
    1) 
    2800
    2) 
    2100
    3) 
    2400
    4) 
    1200

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    Post TestFunda Answers - Higher Maths

    let as take amout as x,(3600-x)
                                        
                                         x*5*4/100 +(3600-x)*5*6/100=960
                             
                       by solving we get x=1200

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    Post TestFunda Answers - Higher Maths

    x  no.of chocolate  in the shop.
    1st person took (x/2+1/2) no.of chocolates.remaining=x-(x/2+1/2)=(x/2-1/2)
    2nd person took1/2*(x/2-1/2)+1/2 n.of choco. remain...=(x/2-1/2)-1/2*(x/2-1/2)+1/2=(x/4-3/4)
    lly after 5th person (x/2^5-31/32)=3 by solving we get x=127

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    Post TestFunda Answers - Higher Maths


    x  no.of chocolate  in the shop.
    1st person took (x/2+1/2) no.of chocolates.remaining=x-(x/2+1/2)=(x/2-1/2)
    2nd person took1/2*(x/2-1/2)+1/2 n.of choco. remain...=(x/2-1/2)-1/2*(x/2-1/2)+1/2=(x/4-3/4)
    lly after 5th person (x/2^5-31/32)=3 by solving we get x=127  


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    Post TestFunda Answers - Higher Maths

    Let r = rate of removing water from the boat
    then
    2r = rate of water leaking into the boat
    :
    let a boat full of water, ready to sink = 1
    :
    30%2Fr - 30%2F%282r%29 = 1
    2(30) - 30 = 2r
    60 - 30 = 2r
    30 = 2r
    r = 15 rate of removing water from the boat
    :
    Find the rate if leak occurs 10 min earlier (40 min to the shore)
    40%2Fr - 40%2F%282r%29 = 1
    2(40) - 40 = 2r
    2r = 40
    r = 20 rate of removing water from the boat
    I guess you could say remove the water; 5/15 = 33% faster  

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    Post TestFunda Answers - Higher Maths

    Let as take amout as x,(3600-x)
    x*5*4/100 +(3600-x)*5*6/100=960
    By solving,
    x=1200  

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    Post TestFunda Answers - Higher Maths

    A boy has Rs 2. He wins or loses Re 1 at a time If he wins he gets Re 1 and if he loses the game he loses Re 1. He can loose only 5 times. He is out of the game if he earns Rs 5. Find the number of ways in which this is possible?

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    Post TestFunda Answers - Higher Maths


    What is the sum of all numbers between 100 and 1000 which are divisible by 14 ?



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    Post TestFunda Answers - Higher Maths


    There are 3 temples and a pond in front of each temple. Anything you dip


    in the pond gets doubled. A person dips X flowers in pond 1 and offers it


    to the God in temple 1. He then dips the remaining flowers in pond 2 and


    offers the same number of flowers to God in temple 2. He then dips the


    remaining flowers in pond 3 and offers it to God in temple 3. He is now left with


    no flowers. How many flowers did he have in the beginning.


    Options
    1) 
    7
    2) 
    6
    3) 
    5
    4) 
    4

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    Post TestFunda Answers - Higher Maths

    The number closest to 100 which is greater than 100 and divisible by 14 is 112, which is the first term of the series which has to be summed.


     The number closest to 1000 which is less than 1000 and divisible by 14 is 994, which is the last term of the series.


    112 + 126 + .... + 994 = 14(8+9+ ... + 71) = 35392  


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    Post TestFunda Answers - Higher Maths


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    Post TestFunda Answers - Higher Maths

    If 3 houses are to be painted, Mr. A can paint a house in 6 days (nos are not same) Mr. B can do the same in 8 days & Mr.C in 12 days. If Mr. A does the work for 8 days & leaves for vacation, & Mr. B continues the work for the next 6 days, for how many days should Mr. C work?
    Options
    1) 
    10
    2) 
    11
    3) 
    12
    4) 
    13

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    Post TestFunda Answers - Higher Maths

    3 houses to be paint.
    Mr.A can paint 1 house in 6 days.
    Mr.B can paint 1 house in 8 days.
    Mr.C can paint 1 house in 12 days.

    If Mr.A paints for 8 days, he paints = 8/6 houses
    If Mr.B paints for 6 days, he paints = 6/8 houses

    So, remaining painting work have to be done by Mr.C is,

    Days to work for Mr.C = 3 - 8/6 + 6/8

    = 3 - 32/24 + 18/24
    = 3 - 50/24
    =(3/1)-(50/24)
    = 72/24 - 50/24
    = 22/24
    = 11/12.

    So, Mr.C working for 11days to complete the remaining painting for house    


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    Post TestFunda Answers - Higher Maths


    A rich man died. In his will, he has divided his gold coins among his 5 sons, 5 daughters and a manager. According to his will: 



    • First give one coin to manager, and 1/5th of the remaining to the eldest son. 

    • Now give one coin to the manager, and 1/5th of the remaining to the second son, and so on and so forth.

    • After giving coins to the 5th son, divide the remaining coins among five daughters equally.

    • Everyone gets an integer number of coins.


    What is the minimum number of coins that the rich man had left behind?


    Additional Notes: I know the long method wala solution but it is very cubersome.So if there is any shortcut please.

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    Post TestFunda Answers - Higher Maths

    A garrison of 750 men has provision for 20 weeks.if at end of the 4 weeks they are reinforced by 450 men,how long will the reamaining provision last?

    Options
    1) 
    10 weeks
    2) 
    11 weeks
    3) 
    15 weeks
    4) 
    16 weeks
    Additional Notes: unitary method

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    Post TestFunda Answers - Higher Maths

    cost of erecting a fence round a square field of 625 hectares at 15 paise per metre is:

    Options
    1) 
    rs.500
    2) 
    rs.750
    3) 
    rs.100
    4) 
    rs.1500
    Additional Notes: unitary method

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