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Thread: TestFunda Answers - Higher Maths

  1. #21
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    Post TestFunda Answers - Higher Maths

    A shop stocks four styles of trousers . For each style, there are 10 different possible waist sizes, 6 different trousers lengths and 4 colour choices. How many different types of trousers could the store  have?
    Options
    1) 
    1024
    2) 
    960
    3) 
    924
    4) 
    921

  2. #22
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    Post TestFunda Answers - Higher Maths

    The total no. of integral solutions for (x,y,z) such that xyz=24 is?
    Options
    1) 
    36
    2) 
    90
    3) 
    120
    4) 
    none of these

  3. #23
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    Post TestFunda Answers - Higher Maths

    Option 4.
    Total possibilities are: 2*26*25*24*10*9*8
    Last digit has to be 0, which is not present in any of the options. 

  4. #24
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    Post TestFunda Answers - Higher Maths

    In how many ways 12 different books can be distributed equally among 4 persons?
    Options
    1) 
    195
    2) 
    154
    3) 
    210
    4) 
    256

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    Post TestFunda Answers - Higher Maths

    4 men and 4 ladies are to be seated around a circular table so that only ladies can sit on two sides of each man?
    Options
    1) 
    72
    2) 
    144
    3) 
    36
    4) 
    56

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    Post TestFunda Answers - Higher Maths

    A person wants to throw as many parties he can out of his 20 friends such that each party consists of the same no. of persons.The no. of friends he should invite at a time is?

    Options
    1) 
    5
    2) 
    8
    3) 
    10
    4) 
    none of these

  7. #27
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    Post TestFunda Answers - Higher Maths

    He should invite 1 friend at a time, so that he can have 20 parties (or date )

  8. #28
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    Post TestFunda Answers - Higher Maths

    It's circular and alternate arrangement, so answer will be 4!*3!=144

  9. #29
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    Post TestFunda Answers - Higher Maths


  10. #30
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    Post TestFunda Answers - Higher Maths

    Answer is 30.
    Following are possible solutions
    1 1 24 (3 arrangement)
    1 2 12 (6)
    1 3 8 (6)
    1 4 6 (6) 
    2 2 6 (3)
    2 3 4 (6)
    Total: 30 

  11. #31
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    Post TestFunda Answers - Higher Maths

    soft drink can be 1 or 2 or 3
    if its 1 it can be selecte din 3 ways, if 2 in 3 ways and if 3 in 1 way

    hence softdrink can be selected in 7 ways
    similarly  for other foods

    hence we get
    7 x 15 x 3= 315

    hence, option 1 

  12. #32
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    Post TestFunda Answers - Higher Maths

    Option 4.
    Total possibilities are: 2*26*25*24*10*9*8
    Last digit has to be 0, which is not present in any of the options. 

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    Post TestFunda Answers - Higher Maths

    a very good framing of the question. According to me the answer is option 3. I think the question just means that u have to choose friends from 20 of them them such that the host can throw maximum no. of parties. From 20 friends the ways of choosing 10 friends is maximum i.e 20c10 is maximum.  therefore he must invite 10 of them in each party...

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  16. #36
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    Post TestFunda Answers - Higher Maths

    a very good framing of the question. According to me the answer is option 3. I think the question just means that u have to choose friends from 20 of them them such that the host can throw maximum no. of parties. From 20 friends the ways of choosing 10 friends is maximum i.e 20c10 is maximum.  therefore he must invite 10 of them in each party...

  17. #37
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    Post TestFunda Answers - Higher Maths

    Answer is 30.
    Following are possible solutions
    1 1 24 (3 arrangement)
    1 2 12 (6)
    1 3 8 (6)
    1 4 6 (6) 
    2 2 6 (3)
    2 3 4 (6)
    Total: 30 

  18. #38
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    Post TestFunda Answers - Higher Maths


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    Post TestFunda Answers - Higher Maths

    It is a circular arrangement
    Four women can be arranged circularly in 3! ways
    Four men can be arranged in 4! ways
    So, total 4!*3! = 144 ways

  20. #40
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