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Thread: TestFunda Answers - Higher Maths

  1. #61
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    Post TestFunda Answers - Higher Maths

    Let h and b be Hans' and Bhaskar's salary
    So,h+b = 10,000
    Let x be the money spend by each of them
    (h-x)/(b-x) = 6/1
    Trying out option 1,
    h=6000 and b=4000
    So, x=3600
    Equations are satisfiedIf amount spent is equal then if the ratio of their savings is to be greater than 1(in this case 6/1=6)
    Then Hans' salary must be greater than Baskrs salary

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    Post TestFunda Answers - Higher Maths

    As per the question,
    Speed on road 1 = 50
    Speed on road 2 = 80/4 =20
    Thus avg speed = 2*50*20/(50+20)=28.56 =29
    Hence, option 2 
    Last edited by vimbloid; 24-Oct-10 at 5:24 PM.

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    Post TestFunda Answers - Higher Maths

    there is only one such set..(5,11,17,23,29)and the avg is 17
    shortcut..since its a set of prime no..avg must also be prime as an ap is formed of 5 nos.. the middle term will be its avg..
    hence ans is either 13 or 17 and only 17 satisfy the conditions
    Last edited by ayyada; 24-Oct-10 at 5:33 PM.

  4. #64
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    Post TestFunda Answers - Higher Maths

    There is only one such set..(5,11,17,23,29)and their average is 17
    Since its a set of prime no..avg must also be prime as an AP is formed of 5 nos..
    The middle term will be its avg..
    Hence answer is either 13 or 17 and only 17 satisfy the conditions

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    Post TestFunda Answers - Higher Maths

    Method 1:

    First male can be selected in 7C1 ways.
    Now, 6 men are left
    First female can be selected in 6C1 ways (as one of them would be the spouse of the first male)
    Now, 6 women are left
    Second male can be selected in 5C1 ways (as one of the 6 males would be the spouse of first female)
    Now, 5 men are left
    Second female can be selected in 4C1 ways (as one of the 5 females would be the spouse of second male)
    Now, 5 women are left

    As when we select M1,M2 we also select M2,M1,
    So, half the selections are redundant
    Desired answer = 7C1*6C1*5C1*4C1/2 = 420 

    Method 2:
    1) select unique groups of 4 people (this would be done using combinations)
    2) multiply the resultant with 2 (i.e for every unique combination of 4 people there are 2 tems possible)
    i.e 7C2 * 5C2 =210
    i.e there are 210 unique combinations of the 4 people 
    so nos of teams = 2*210
    =420 
    Last edited by vimbloid; 24-Oct-10 at 8:11 PM.

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    Post TestFunda Answers - Higher Maths

    10 students = 7 boys + 3 girls
    No two girls should sit together
    So, lets place the boys first
    The boys can be placed in a row in 7! ways
    There are 8 spaces between these boys
    The girls have to be placed in these 8 places. This can happen in 8C3 ways 
    Then, these 3 girls can be seated in 3! ways
    So, desired answer = 8C3*7!*3! ways 

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    Post TestFunda Answers - Higher Maths

    There are seven people sitting around a table. Each person has a
    glass of water, the total amount of water in their glasses being
    equivalent to 3 glasses of water. Rohan, sitting at the head of the table,
    takes his water and distributes it equally among others. Then the
    person to the right of Rohan does the same, evenly giving away his
    water. Every person does this until it comes back to Rohan, when they
    all examine their glasses and realize that they have the same amount
    they started with!
    A: How much water did each person have?
    B: How many different water combinations are possible? (Show
    proof)
    C: Is there a solution if the number of people is infinite?
    Caselet
     

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    Post TestFunda Answers - Higher Maths

    A man sell an article at 5% above its cost price .If the had bought it at 5% less than what he paid for it and sold for @s.2 less , he would have gained 10%.Find the cost price of the article.
    Options
    1) 
    500
    2) 
    400
    3) 
    425
    4) 
    360
    Last edited by jayavignesh; 26-Oct-10 at 9:22 AM.

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    Post TestFunda Answers - Higher Maths

    A brief case was sold at a profit of 10% .If it s cost price was 5% less and it was sold for Rs.7 more the gain would have been 20%.Find the cost price of the brief case?
    Options
    1) 
    175
    2) 
    200
    3) 
    225
    4) 
    160

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    Post TestFunda Answers - Higher Maths

    A man buys two cycles for a total cost of Rs .900.By  selling one for 4/5 of its cost and other for 5/4 of its cost, he makes a profit of Rs.90 on the whole transaction.find the cost price of lowe priced cycle
    Options
    1) 
    360
    2) 
    300
    3) 
    250
    4) 
    420

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    Post TestFunda Answers - Higher Maths

    Option 2.
    working through options.
    Initially, selling price: Rs. 378

    Now, buying price: Rs. 342
    Selling price: 376

    We have the answer. 

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    Post TestFunda Answers - Higher Maths

    option 2.
    Two equations:
    x+y = 900
    (4/5)x + (5/4)y = 990

    Solving this, x=300, y=600

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    Post TestFunda Answers - Higher Maths

    A: Whatever they had to start with. 3 glasses of water.

    B: Total 13 combinations.
    2 combinations: when first person distributes (water available to first person, water available to rest of people) 
    2 combinations: when second person distributes (water available to first and second person, water available to rest of people)
    .
    .
    ?2 combinations: when sixth person distributes (water available to 1 to 6 persons, water available to 7th person)
    1 combination: water available to all people (or water available at start)

    C: Yes, as this is cyclical process, it will have solution for whatever number of persons involved.

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    Post TestFunda Answers - Higher Maths

    Case 1: Let CP be x. Then, SP = 1.05x
    Case 2: New CP=0.95x, then, SP= 1.05x-2, Profit=10%

    0.1= (1.05x-2-0.95x)/0.95x
    Solving above eq. we get
    x= 400

    Last edited by vimbloid; 26-Oct-10 at 9:22 AM.

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    Post TestFunda Answers - Higher Maths

    The answer is option 2
    Two equations:
    x+y = 900
    (4/5)x + (5/4)y = 990

    Solving this, x=300, y=600

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    Post TestFunda Answers - Higher Maths


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    Post TestFunda Answers - Higher Maths

    after 16 years........their combine age will be 80 years

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    Post TestFunda Answers - Higher Maths

    there will be 90 memebers coz increasing the members by 10 will decrease the cost by 15 so.....increasing 40 memebers decreases the cost by 60 rs.....and 220-60=120...hence nuber os memebers will be 90

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