We can also solve this problem by upside down addition method as follow
s n u b
c o i n
----------------------
c o u n t
----------------------
Here c must be 1 which is carry forward by 2nd column.(c=1)
s n u b
1 o i n
--------------
1 o u n t
--------------
So s must be 9 for giving a carry to 1st column.(s=9)
Then s+1=9+1=10, so o=0(zero).
9 n u b
1 0 i n
---------------
1 0 u n t
----------------

by solving following equations we get results.

From 3rd column
If carry is not forwarded to dis column then N=U, so its not possible.
So
N+0+1=U
N+1=U

From 4th column,
If carry is not forwarded by 4th column.
Then

U+I=N+10 (U=N+1)
Then I=9. It is not possible y bcoz s=9,

So carry must come

1+U+I=N+10,
I=8,

9 N U B
1 0 8 N
-----------
1 0 U N T
------------

First race all 25 in groups for 5 to figure out top 3 in each group. (15 left) Call them A1 B1 C1 D1 E1 A2 B2 C2 D2 E2 A3 B3 C3 D3 E3 Here A1 is faster than A2. A2 is faster than A3. The same applies for the rest of the groups.

Now race A1, B1 C1 D1 E1

Lets say the order of the horses according to ranking was A1, B1,C1,D1,E1

So A1 is No 1

Now A1 is faster than B1 and B1 is faster than C1. So we can get rid of the entire D and E groups 9 horses remaining

Also A1 is faster than B1 and B1 is faster than C1. So we can get rid of C2 and C3 7 horses remaining

A1 is faster than B1. B1 is faster than B2. get rid of B3 6 horses remaining

Out of these, We know A1 is the fastest. So now race A2, A3, B1,B2,C1 to figure out No2 and No3 positions

One of the following is my secret word:AIM DUE MOD OAT TIE.With the list in front of you, if I were to tell you any one of my secret word, then you would be able to tell me the number of vowels in my secret word.Which is my secret word?

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