Let *e* be the age of eldest, *y* be the age of middle one, and *s* be the age of youngest

from given data we can deduce the following

e-y = 3 or e-s =3 or y-s =3

e = 3s

e = 2+ y + s

3s = 2 + y + s

2s = 2 + y

Assume e-y =3

3 = 2+s

s = 1

e = 3

y = 0 (not possible)

assume e-s = 3

3+s = 3s

2s = 3

s = 1.5

e = 4.5

y = 1.5 not possible because there is youngest child hence s and y should be distinct

assume y-s = 3

2s = 2+3+s

s = 5

y = 8

e = 15

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