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Thread: TestFunda Answers - Logical Reasoning

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    Post TestFunda Answers - Logical Reasoning


    ‘S’ is the set of all natural numbers up to 75. If ‘a’ is the sum of all numbers in S which leave a

    reminder 1 when divided by 4 and ‘b’ is the sum of all numbers in S which leave a reminder 3 when

    divided by 4, the difference between a and b is?

    Options
    1) 
    72
    2) 
    36
    3) 
    38
    4) 
    76

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    Post TestFunda Answers - Logical Reasoning


    Let S= {1, 2, 3, 4, 5, 6}. If a, b are selected from S such that b < a. Find the number of pairs such

    that a!/b! is divisible by 3.

    Options
    1) 
    11
    2) 
    12
    3) 
    13
    4) 
    14

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    Post TestFunda Answers - Logical Reasoning


    Number of exchanges within a family = 15 × 4 × 3

    = 180

    Number of exchanges within a family = 15 × 4 × 3= 180

    Number of exchanges between families = 15 × 14= 210

    Total number of bouquests = 390 

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    Post TestFunda Answers - Logical Reasoning


    Taking sets of four consecutive natural numbers at

    a time(1-4, 5-8&hellip, we find that each quartet makes

    raises the difference between ‘a’ and ‘b’ by

    2 (3 – 1 = 7 – 5 =.....= 2).

    There are 18 such quartets up to 72. 73 and 75 yield a

    further difference of 2. Thus the difference is 38.

    Taking sets of four consecutive natural numbers ata time(1-4, 5-8&hellip, we find that each quartet makes the difference between ‘a’ and ‘b’ by 2 (3 – 1 = 7 – 5 =.....= 2).There are 18 such quartets up to 72. 73 and 75 yield a further difference of 2. Thus the difference is 38.

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    Post TestFunda Answers - Logical Reasoning


    Substituting values for ‘a’ and counting the number of

    feasible values of b, the number of pairs we have is

    0 + 0 + 2 + 2 + 2 + 5 = 11.

    Substituting values for ‘a’ and counting the number offeasible values of b, the number of pairs we have is 0 + 0 + 2 + 2 + 2 + 5 = 11.

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    Post TestFunda Answers - Logical Reasoning

    Statements : All mangoes are golden in colour.No golden-coloured things are cheap.
    Conclusions : I. All mangoes are cheap.
                        II. Golden-coloured mangoes are not cheap.                                                                                                           
    Options
    1) 
    if only conclusion I follows
    2) 
    if only conclusion II follows
    3) 
    if either conclusion I or II follows
    4) 
    if neither conclusion I or II follows
    5) 
    if both conclusion I or II follows
    Additional Notes: please i need an answer to this question with an explanation

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    Post TestFunda Answers - Logical Reasoning

    See all mangoes are golden and no golden is cheap that means no mango is cheap.

    SO conclusion I is wrong , also we know golden colored mangoes are not cheap.

    So only conculsion II follows 
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    Post TestFunda Answers - Logical Reasoning

    Two squares are chosen at random on a chessboard. What is the probability that they have a side in common? 
    Options
    1) 
    1 / 18
    2) 
    64 / 4032
    3) 
    63 / 64
    4) 
    1 / 9

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    Post TestFunda Answers - Logical Reasoning


    The number of ways of choosing the first square is 64. The number of ways of choosing the second square is 63. There are a total of 64 * 63 = 4032 ways of choosing two squares. 

     

    If the first square happens to be any of the four corner ones, the second square can be chosen in 2 ways. If the first square happens to be any of the 24 squares on the side of the chess board, the second square can be chosen in 3 ways. If the first square happens to be any of the 36 remaining squares, the second square can be chosen in 4 ways. Hence the desired number of combinations = (4 * 2) + (24 * 3) + (36 * 4) = 224. Therefore, the required probability = 224/4032 = 1/18 

     

    The number of ways of choosing the first square is 64. The number of ways of choosing the second square is 63. There are a total of 64 * 63 = 4032 ways of choosing two squares. 
    If the first square happens to be any of the four corner ones, the second square can be chosen in 2 ways. If the first square happens to be any of the 24 squares on the side of the chess board, the second square can be chosen in 3 ways. If the first square happens to be any of the 36 remaining squares, the second square can be chosen in 4 ways. Hence the desired number of combinations = (4 * 2) + (24 * 3) + (36 * 4) = 224. Therefore, the required probability = 224/4032 = 1/18 

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    Post TestFunda Answers - Logical Reasoning

    answer on the basis of he pattern-\
    Input- smile, nile, style, mile, shine, wine, mine, swine, bovine, feline
    step 1: smile, nile, style, mile, shine, wine, bovine, feline, mine, swine.
    step 2: style, mile, smile, nile, shine, wine, bovine, feline, mine, swine
    step 3: style, mile, smile, nile, wine, shine, bovine, feline, mine, swine
    step  4: mile, style, nile, smile, wine, shine, feline, bovine, swine, mine,
    step 5: nile, smile, mile, style, wine, shine, swine, mine, feline, bovine,
    step 6: nile, smile, mile, style, wine,shine,feline.bovine,swine,mine
    step 7: mile, style, nile, smile,wine, shine,feline, bovine, swine. mine.

    WHAT WILL BE STEP 14
    Options
    1) 

    DETAILED EXPLANATION IS SOUGHT

    2) 

    HOW TO APPROACH

    3) 
    LOGIC PATTERN

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    Post TestFunda Answers - Logical Reasoning

    Take input as : 1 2 3 4 5 6 7 8 9 10
    where 1 is smile 2 is nile and so on

    Now for first step it is : 1 2 3 4 5 6 9 10 7 8
    2nd : 3 4 1 2 5 6 9 10 7 8
    3rd : 3 4 1 2 6 5 9 10 7 8
    4th : 4 3 2 1 6 5 10 9 8 7
    5th : 2 1 4 3 6 5 8 7 10 9

    Then from 6th step onward same pattern as step 1. Thus find answer 

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    Post TestFunda Answers - Logical Reasoning


    A sheet of paper has statements numbered from 1 to 40. For each value of n from 1 to 40, statement n says "At least n of the statements on this sheet are true." Which statements are true and which are false?


    Options
    1) 
    The first 26 statements are false and the rest are true.
    2) 
    The odd numbered statements are true and the even numbered are false.
    3) 
    The even numbered statements are true and the odd numbered are false.
    4) 
    The first 13 statements are true and the rest are false.

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    Post TestFunda Answers - Logical Reasoning

    1) if first 26 statements are false and the 40th statement states that atleast 40 of these statements will be true is a contradiction.
    2) If the odd statement is true, then atleast 39 statements are true is a contradiction.
    3) same as statement 2
    4) This could be a possibility

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    Post TestFunda Answers - Logical Reasoning


    Alok and Bhnau play the following min-max game. Given the expression N=X-Y-Z



    where X,Y,Z are variables representing single digits (0-9). ALok would like to maximize N while Bhanu tries to minimize it, Towards the end, ALok cgooses a single digit number and Bhanu chooses the variable of his choice (X,Y,Z)to substitute the value. Alok then chooses the next value and Bhanu the variable to substitutes the value. Finally Alok proposes the value for the remaining variable. Assuming both play optimal strategies, the value of N at the end would be?


    Options
    1) 
    9
    2) 
    -18
    3) 
    4
    4) 
    2

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    Post TestFunda Answers - Logical Reasoning

     0-9 digits.... The basic idea is to get maximum value.... so if alok chooses anything more than or equal to 3 then he going to end up only with a maximum of 1... example if he takes 3 and banu will choose either y or z coz if she chooses x then alok will suggest remaining values as 0 and 0... now for the second try he has to choose a value more than 3 or else bhanu will choose that value for x and N will become negative at the end.... if he chooses 4 then banu will assign it to x thus keeping the value of X to 1.. and if chooses 5 then she ll assign it z.. Thus value is kept to maximum of 1....
    Now lets say alok chooses 2.... banu will try to put it to y or z.... now alok chooses 4.. then she ll choose it for x.. thus keeping the value of N to 2.. if alok chooses 5 on second try then she ll assign for z thus again keeping the value down to 2.....

    So only 2 can be Achieved as maximum value for N if they both play optimally.....
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    Post TestFunda Answers - Logical Reasoning

    Option 1,2 and 3 can be eliminated
    option 1 : if the statement 'atleast 26 statements are true' is false then 'atleast 27 statements are true' is also false
    option 2 : if 'atleast 3 statements are true' then 'atleast 2 statements are true' should be true and similarly for option 3 

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    Post TestFunda Answers - Logical Reasoning

    Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the present age of Peter?

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    Post TestFunda Answers - Logical Reasoning


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    Post TestFunda Answers - Logical Reasoning

    Let x be age of peter now and y be age of paul now
    x + y = 35
    Now consider 'a' years ago the condition given in the question happens
    thus x - a = y
    y - a = y/2
    so we get a = y/2
    thus we get x = 3y/2
    So substituting in the original eqn
    3y/2 + y = 35
    y = 14
    x = 21 

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    Post TestFunda Answers - Logical Reasoning

     

    A hunter leaves his cabin early in the morning and walks one mile due south. Here he sees a bear and starts chasing it for one mile due east before he is able to shoot the bear. After shooting the bear, he drags it one mile due north back to his cabin where he started that morning. What color is the bear?


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