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Thread: Quant Thread For CAT 2011

  1. #61
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    Quote Originally Posted by grimreaper View Post
    i see your point... but then how did u arrive at this... i mean... u take the condition of each day 6 men more to the initial problem itself right...

    but even then... i can only think of trial and error to get at this table....
    even then i wnt be sure till my total comes upto 545....

    i mean yes i would have started with only one man on the first day... but nonetheless... i still wld have to calculate all the way till day 5 to be sure....
    but yes the table is right

    @ mohsan - post your method for that circular Question..... lets see what you did , and try the previous Qs posted in this forum...
    @GrimSaar:

    I need to learn such shortcuts and quckmethods...please do help me with tips and suggestions...
    I'm pretty old fashioned

    Assumed x as no of men on 1st day and N as no. of crates/men on 1st day

    x.N + (x+6)(N-5) + (x+12)(N-10) + (x+18)(N-15) + (x+24)(N-20) = 545
    (x+12)(N-10)=169
    Clearly N>20
    So, X=1 and N=23...
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    Quote Originally Posted by grimreaper View Post
    yup.... an easy prob ... ehmmm bt x=2006 :P not 1003....
    oops !!.... yeah its 2006 !

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    Quote Originally Posted by shaunak_87 View Post
    @GrimSaar:

    I need to learn such shortcuts and quckmethods...please do help me with tips and suggestions...
    I'm pretty old fashioned

    Assumed x as no of men on 1st day and N as no. of crates/men on 1st day

    x.N + (x+6)(N-5) + (x+12)(N-10) + (x+18)(N-15) + (x+24)(N-20) = 545
    (x+12)(N-10)=169
    Clearly N>20
    So, X=1 and N=23...
    I guess, with nothing else mentioned, the only way thru this question was the long way.... however, calculation can b eased a bit using AP summation.

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    Read the information given below and answer the question that follows:

    Kallu kallan kalia's night club number is a 3 digit perfect square.This number when written in the reverse order also gives a perfect square and is telephone extension of kallu's office.His Mercedes registration number is a four digit perfect square formed by repeating the right most digit of his nightclub number.
    The sum of the digits of kallu's night club number is

    (A) a perfect square
    (B) an even number
    (C) a prime number
    (D) a perfect number

  5. #65
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    Quote Originally Posted by mohasan02 View Post
    I guess, with nothing else mentioned, the only way thru this question was the long way.... however, calculation can b eased a bit using AP summation.
    Somehow i feel that the method is not too long and can u elaborate on AP summation for this, causse there are 5 products and can be easily reduced

    I feel the sum was made for the part
    (x+12)(N-10)=13*13 part...means the factorization part....
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  6. #66
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    Quote Originally Posted by anjalig View Post
    Read the information given below and answer the question that follows:

    Kallu kallan kalia's night club number is a 3 digit perfect square.This number when written in the reverse order also gives a perfect square and is telephone extension of kallu's office.His Mercedes registration number is a four digit perfect square formed by repeating the right most digit of his nightclub number.
    The sum of the digits of kallu's night club number is

    (A) a perfect square
    (B) an even number
    (C) a prime number
    (D) a perfect number
    hmmmm.... well i assume that when you say repeating the last most digit it means adding the digits once again at the end.... rather than repeatin the same digit four times cause else such a number can never be a perfect square.... since "aaaa" means 1111*a which cant be a square.

    so said that... your number would be 144
    when read backwards its 441 = 21^2
    and the last digit repeated gives 1444 = 38^2

    so well sum is 9 and its a perfect square....

    though i dnt knw wht a perfect number means
    so going with option a

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    Quote Originally Posted by shaunak_87 View Post
    @GrimSaar:

    I need to learn such shortcuts and quckmethods...please do help me with tips and suggestions...
    I'm pretty old fashioned

    Assumed x as no of men on 1st day and N as no. of crates/men on 1st day

    x.N + (x+6)(N-5) + (x+12)(N-10) + (x+18)(N-15) + (x+24)(N-20) = 545
    (x+12)(N-10)=169
    Clearly N>20
    So, X=1 and N=23...
    hmmmm well first thing you gotta be lazy... and hate equations.... : P:P

    its nothing much man.... just hold yourself from going at the equations always...thts all......
    but to be frank at times equations are the best way out too .... nt all prob have a shortcut...

    ok now you must be going like

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    Quote Originally Posted by anjalig View Post
    Read the information given below and answer the question that follows:

    Kallu kallan kalia's night club number is a 3 digit perfect square.This number when written in the reverse order also gives a perfect square and is telephone extension of kallu's office.His Mercedes registration number is a four digit perfect square formed by repeating the right most digit of his nightclub number.
    The sum of the digits of kallu's night club number is

    (A) a perfect square
    (B) an even number
    (C) a prime number
    (D) a perfect number
    four digit perfect square formed by same digit can be 0000
    night club number = 400
    Not sure
    400---004---0 being right most digit of 400....Car no being 0000
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    Quote Originally Posted by grimreaper View Post
    hmmmm.... well i assume that when you say repeating the last most digit it means adding the digits once again at the end.... rather than repeatin the same digit four times cause else such a number can never be a perfect square.... since "aaaa" means 1111*a which cant be a square.

    so said that... your number would be 144
    when read backwards its 441 = 21^2
    and the last digit repeated gives 1444 = 38^2

    so well sum is 9 and its a perfect square....

    though i dnt knw wht a perfect number means
    so going with option a
    Exactly,
    aaaa can't be a perfect sqr...so the qstn seems ambiguous

    thanks Grim Saar
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    Quote Originally Posted by shaunak_87 View Post
    four digit perfect square formed by same digit can be 0000
    night club number = 400
    Not sure
    400---004---0 being right most digit of 400....Car no being 0000
    no no... i think its only last digit repeated once...

    so number wld be 144 , 441 and 1444 else Question wnt hold....

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    Quote Originally Posted by grimreaper View Post
    no no... i think its only last digit repeated once...

    so number wld be 144 , 441 and 1444 else Question wnt hold....
    Thank U Saar
    20^2,12^2,21^2,13^2,31^2,22^2 all have this PROP...

    tHANK U SARR
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    The value of A + B that satisfies (6^30 + 6^-30) (6^30 - 6 ^-30) =
    3^A8^B-3^-A 8^-B is

    A. 20
    B. 60
    C. 80
    D. 40

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    plz solve ths..
    king nandan is the king divyagarh.One day he decides to sell all the animals living in his big kingdom.Now,there are five states in his kingdom and the only animals which his kingdom is having are horses ,cows and sheeps.King sells all the animals to eight neighbouring states.Each of the neighbouring states purchases same number of animals at the following rate.
    horse-1700 each
    cow-200 each
    sheep-200 each
    king nandan receives rs 28,500 in all.

    what can be the maximum number of animals?
    Options
    1) 80
    2) 130
    3) 160
    4) none of these

    what are the respective numbers of horses,cows and sheeps in any state?
    Options
    1) (3,109,8)
    2) (1,37,3)
    3) (2,74,6)
    4) cannot be determined

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    these profit loss questns r killin me !

    machine X produces articles at the rate of 50 units/h.SP of each article is rs 100
    and the cost of production is rs 40 each.However 20% of the articles are defective and hence cannot be sold.The rate of production of machine can be increased,but with every increase of N units/h production cost would increase by 2x% and the number of defectives would become (20+1.5x)%.

    1)find the maximum increase in production that can be undertaken without incurring losses?
    a)14 units
    b)15 units
    c)16 units
    d)17 units

    2)What will be the profit in 1hr if the machine produces 58 units/hr?
    a)Rs 1839
    b)Rs 1178
    c)Rs 1253
    d)Rs 1624

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    Quote Originally Posted by anjalig View Post
    The value of A + B that satisfies (6^30 + 6^-30) (6^30 - 6 ^-30) =
    3^A8^B-3^-A 8^-B is

    A. 20
    B. 60
    C. 80
    D. 40

    option C. This can be worked out orally, but is a very good question, owing to its intimidating form when faced in CAT like time crunch !

    Solution: (630+6-30)(630-6-30) = (660-6-60)
    = 820.360-8-20.3-60...(i)

    Comparing powers of (i) & the given RHS, we get B=20 ; A=60.


    *Note -It would be gr8 to follow question numbering, as suggested by grimreaper. It wud help us keep a track !

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    Quote Originally Posted by quixotic_me View Post
    these profit loss questns r killin me !

    machine X produces articles at the rate of 50 units/h.SP of each article is rs 100
    and the cost of production is rs 40 each.However 20% of the articles are defective and hence cannot be sold.The rate of production of machine can be increased,but with every increase of N units/h production cost would increase by 2x% and the number of defectives would become (20+1.5x)%.

    1)find the maximum increase in production that can be undertaken without incurring losses?
    a)14 units
    b)15 units
    c)16 units
    d)17 units

    2)What will be the profit in 1hr if the machine produces 58 units/hr?
    a)Rs 1839
    b)Rs 1178
    c)Rs 1253
    d)Rs 1624
    Juz had a glance thru ur question while in office (during lunch time), so not enuff time to post an entire solution... Though i may suggest a hint for you to try -
    Taking 1 hr to be unit time :-

    Max profit = 2000/-. Now an increase of N would increase CP by (x/50) & unused good by (20+1.5x)/100 [which means sales reduce in proportion of (20+1.5x)/100 ] Form the equation : SP = CP in terms of N & x and may be u express N interms of x - from where u may get max. N by putting some hit & trial value of x

    I am sorry for not being able to write the entire solution due to lack of time ... kindly post, if the above hint helps u

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    Quote Originally Posted by mohasan02 View Post
    Juz had a glance thru ur question while in office (during lunch time), so not enuff time to post an entire solution... Though i may suggest a hint for you to try -
    Taking 1 hr to be unit time :-

    Max profit = 2000/-. Now an increase of N would increase CP by (x/50) & unused good by (20+1.5x)/100 [which means sales reduce in proportion of (20+1.5x)/100 ] Form the equation : SP = CP in terms of N & x and may be u express N interms of x - from where u may get max. N by putting some hit & trial value of x

    I am sorry for not being able to write the entire solution due to lack of time ... kindly post, if the above hint helps u

    thanx fr d hint.. tried..bt nt getting d answer.. plz tell me whr m wrong.. got following two eqns

    (50+n)40 - 2000=x/50 *2000
    so ,n= x

    whr 2000 is the cost price of original 50 items.

    now sp=cp
    100(50+n) - [(20+1.5x)/100 ](50+n)100=2000+ x/50 * 2000
    since x=n
    3n^2+70n-4000=0

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    Quote Originally Posted by anjalig View Post
    The value of A + B that satisfies (6^30 + 6^-30) (6^30 - 6 ^-30) =
    3^A8^B-3^-A 8^-B is

    A. 20
    B. 60
    C. 80
    D. 40
    ok.... well answer would be 80

    when you see the lhs...realise it is nothing but a^2-b^2 form..
    hence u knw the only way 2^n*3^b = some 6^t is when n=b=t
    hence directly a=3b here
    also... a/2=30 as can be seen directly...
    so a=60 b=20
    so answer is 80

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    Quote Originally Posted by quixotic_me View Post
    thanx fr d hint.. tried..bt nt getting d answer.. plz tell me whr m wrong.. got following two eqns

    (50+n)40 - 2000=x/50 *2000
    so ,n= x

    whr 2000 is the cost price of original 50 items.

    now sp=cp
    100(50+n) - [(20+1.5x)/100 ](50+n)100=2000+ x/50 * 2000
    since x=n
    3n^2+70n-4000=0
    huh?? why are you bringing that 2000 into the equation... i mean that value isnt constant....
    you only need to equate the S.P for a giving production = the C.P for a given x

    S.P=100*(50+x)( 1- defect %)
    C.P= (50+x)(40 + 40*2x/100)

    but for some reason i am getting 17.3 as answer....
    and the profit as 1252.8 as the answer...
    u gt the answer with you ??

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    Quote Originally Posted by grimreaper View Post
    huh?? why are you bringing that 2000 into the equation... i mean that value isnt constant....
    you only need to equate the S.P for a giving production = the C.P for a given x

    S.P=100*(50+x)( 1- defect %)
    C.P= (50+x)(40 + 40*2x/100)

    but for some reason i am getting 17.3 as answer....
    and the profit as 1252.8 as the answer...
    u gt the answer with you ??
    oh yeah !! u got it right !!answer is 17 units and 1253
    thanx a tonnnnn !!

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