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Thread: Quant Thread For CAT 2011

  1. #81
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    Default A doubt

    Remainder when 22^33 /45 ??...help plzz.

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    Quote Originally Posted by grimreaper View Post
    huh?? why are you bringing that 2000 into the equation... i mean that value isnt constant....
    you only need to equate the S.P for a giving production = the C.P for a given x

    S.P=100*(50+x)( 1- defect %)
    C.P= (50+x)(40 + 40*2x/100)

    but for some reason i am getting 17.3 as answer....
    and the profit as 1252.8 as the answer...
    u gt the answer with you ??
    First, sorry for the late posting. Seems you got the answer right !!

    Jus one doubt -- In the equations for CP & SP, i guess (50+x) is to be replaced by (50+N) b`cuz, I got the same equations

    S.P. = [1-(20+1.5x/100)][50+N].100
    C.P. = [50+N][40+40.(x/50)]

    Though on equating, [50+N] will cancel out !!.. But yeah the equations are correct

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    Quote Originally Posted by mohasan02 View Post
    First, sorry for the late posting. Seems you got the answer right !!

    Jus one doubt -- In the equations for CP & SP, i guess (50+x) is to be replaced by (50+N) b`cuz, I got the same equations

    S.P. = [1-(20+1.5x/100)][50+N].100
    C.P. = [50+N][40+40.(x/50)]

    Though on equating, [50+N] will cancel out !!.. But yeah the equations are correct
    frm d eqn
    new cp- old cp =increase in productn cost
    (50+n)40 - 2000=x/50 *2000 u get
    n= x so,it doesnt mattr whethr u write x or u write n.. i think dats y he has writn 50+x instead of 50+n ..

  4. The Following User Says Thank You to quixotic_me For This Useful Post:

    mohasan02 (01-Apr-11)

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    Quote Originally Posted by amrit.pati View Post
    Remainder when 22^33 /45 ??...help plzz.
    i think itz 43.. is it correct?

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    Default Q 11.

    Kindly follow question number from here-on . I have considered numbering all the questions after Q.5 !! Here is a question from my side -

    The function "f" is defined on the set of integers and

    f(n) = (n-4) ; if n>2008
    = f{f(n+6)} ; if n<2008

    Find f(95)

    a. 2003
    b. 2007
    c. 2005
    d. 2006
    e. 2004

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    Quote Originally Posted by mohasan02 View Post
    Kindly follow question number from here-on . I have considered numbering all the questions after Q.5 !! Here is a question from my side -

    The function "f" is defined on the set of integers and

    f(n) = (n-4) ; if n>2008
    = f{f(n+6)} ; if n<2008

    Find f(95)

    a. 2003
    b. 2007
    c. 2005
    d. 2006
    e. 2004
    op c.2005
    CAT2011 : 99.97%ile
    XAT2012 : 99.07%ile
    FMS 2012-14
    Other Converts : IIML, MDI, NITIE, SJMSOM,IIM RRR

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    Quote Originally Posted by amrit.pati View Post
    Remainder when 22^33 /45 ??...help plzz.
    Denominator = 5*9

    When 22^33 is div by 5 remainder is 2
    When 22^33 is div by 9 remainder is 1
    So actual rem is the smallest no which gives a rem of 2 when div by 5 & rem of 1 when div by 9.
    Hence actual rem is 37
    CAT2011 : 99.97%ile
    XAT2012 : 99.07%ile
    FMS 2012-14
    Other Converts : IIML, MDI, NITIE, SJMSOM,IIM RRR

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    Quote Originally Posted by shaunak_87 View Post
    op c.2005
    plz post ur solution !

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    Quote Originally Posted by shaunak_87 View Post
    op c.2005
    .... kindly post your solution. evn i`ll post my method.... Infact, I am not very satisfied with my method. IN any case, it would be great to share different approaches for a problem

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    Default My method for Q.11

    Quote Originally Posted by mohasan02 View Post
    Kindly follow question number from here-on . I have considered numbering all the questions after Q.5 !! Here is a question from my side -

    The function "f" is defined on the set of integers and

    f(n) = (n-4) ; if n>2008
    = f{f(n+6)} ; if n<2008

    Find f(95)

    a. 2003
    b. 2007
    c. 2005
    d. 2006
    e. 2004
    From the given expression, we infer that

    f(2009) = 2005
    f(2007) = f{f(2013)} = f {2009} = 2005 ....... (i)
    f(2005) = f{f(2011)} = f{2007} = 2005 ........ obtained from (i)
    f(2003) = f{f(2009)} = f{2005} = 2005
    f(2001) = f{f(2007)} = f{2005} = 2005
    .
    .
    .
    .
    .

    f(odd terms) = 2005

    therefore f(95) = 2005

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    Default Q12

    plz solve ds one ...
    Find the highest natural number N less than 400,such that N can be written as sum of consecutive natural numbers in 11 ways ,but cannot be written as sum of 11 consecutive numbers.

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    Default Q13

    and ds one too..
    A number N when divided by divisor D gives a remainder of 52.The number 5N when divided by D gives a remainder of 4.How many values of D are possible?

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    Quote Originally Posted by quixotic_me View Post
    and ds one too..
    A number N when divided by divisor D gives a remainder of 52.The number 5N when divided by D gives a remainder of 4.How many values of D are possible?
    a nice Q.... getting 9 values as the answer... so well if its right wld post my method.....

  15. #94
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    Quote Originally Posted by quixotic_me View Post
    plz solve ds one ...
    Find the highest natural number N less than 400,such that N can be written as sum of consecutive natural numbers in 11 ways ,but cannot be written as sum of 11 consecutive numbers.
    getting answer as 315 .... nice set of Qs...

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    Quote Originally Posted by quixotic_me View Post
    and ds one too..
    A number N when divided by divisor D gives a remainder of 52.The number 5N when divided by D gives a remainder of 4.How many values of D are possible?
    Ans should be 3

    D={64,128,256}
    CAT2011 : 99.97%ile
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    Quote Originally Posted by quixotic_me View Post
    plz solve ds one ...
    Find the highest natural number N less than 400,such that N can be written as sum of consecutive natural numbers in 11 ways ,but cannot be written as sum of 11 consecutive numbers.
    Getting 315 = 3^2*5*7 as the No.
    CAT2011 : 99.97%ile
    XAT2012 : 99.07%ile
    FMS 2012-14
    Other Converts : IIML, MDI, NITIE, SJMSOM,IIM RRR

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    Quote Originally Posted by grimreaper View Post
    a nice Q.... getting 9 values as the answer... so well if its right wld post my method.....
    @Grim:

    D should be >52 and the values of D will be D=64,128,256 i guess.

    Pardon me if i'm wrong...
    CAT2011 : 99.97%ile
    XAT2012 : 99.07%ile
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    Quote Originally Posted by grimreaper View Post
    Q4) 3*2^p + 5^q + 7^r + 11^s =2008 what is the value of p+q+r+s, where all are greater than 0
    a)9
    b)10
    c)24
    d)15
    e)unique solution does not exist
    Quote Originally Posted by shaunak_87 View Post
    op e)unique solution does not exist

    p q r s
    0 4 2 3
    9 0 3 2
    hi guys,

    Isn't mentioned that all values are to be greater than zero.

    Is there any other method other than trial and error for this question.

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    Quote Originally Posted by shaunak_87 View Post
    @Grim:

    D should be >52 and the values of D will be D=64,128,256 i guess.

    Pardon me if i'm wrong...
    oh ya,... sigh such mistakes :|....
    D has to be more than 52....
    so 3 such values..... 64 128 256

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    Quote Originally Posted by Rajasekaran View Post
    hi guys,

    Isn't mentioned that all values are to be greater than zero.

    Is there any other method other than trial and error for this question.
    oh sorry about that.. inlcude 0 too ... greater than equal to zero...
    and yes there is a proper method to do this prob.....
    try it... wld post the solution then... just that noone tried it at all...apart from shaunak... so didnt post the solution as of yet......

    @all - give it a try

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